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From: Frank Terbeck <ft@bewatermyfriend.org>
To: "Benjamin R. Haskell" <zsh@benizi.com>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: Assign to parameter in parameter -- opposite of ${(P)name}?
Date: Sat, 10 Jul 2010 03:13:47 +0200	[thread overview]
Message-ID: <87fwzst9ys.fsf@ft.bewatermyfriend.org> (raw)
In-Reply-To: <alpine.LNX.2.01.1007091908420.4808@hp.internal> (Benjamin R. Haskell's message of "Fri, 9 Jul 2010 19:17:38 -0400 (EDT)")

Benjamin R. Haskell wrote:
> It's the end of the week, and I'm tired, so I'm sure I'm completely 
> overlooking something obvious, but how do you *assign* to a parameter 
> whose name is in a parameter?
[...]
> Do I need to resort to 'eval'?

% typeset foobar=baz
% print ${foobar}
baz

Regards, Frank

-- 
In protocol design, perfection has been reached not when there is
nothing left to add, but when there is nothing left to take away.
                                                  -- RFC 1925


  reply	other threads:[~2010-07-10  1:27 UTC|newest]

Thread overview: 8+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2010-07-09 23:17 Benjamin R. Haskell
2010-07-10  1:13 ` Frank Terbeck [this message]
2010-07-10 15:36   ` Benjamin R. Haskell
2010-07-10 15:44     ` Frank Terbeck
2010-07-10 15:54       ` Benjamin R. Haskell
2010-07-10 14:57 ` Julius Plenz
2010-07-10 15:52   ` Benjamin R. Haskell
2010-07-10 17:39 ` Bart Schaefer

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