* complete question
@ 1997-04-14 20:12 Steve Talley
1997-04-14 21:54 ` blaise
0 siblings, 1 reply; 2+ messages in thread
From: Steve Talley @ 1997-04-14 20:12 UTC (permalink / raw)
To: zsh-users
I have a command "beroot" that executes any arguments as root. i.e.
% beroot id -a
prints out:
uid=0(root) gid=10(staff) groups=10(staff),14(sysadmin)
How can I get zsh to complete the first parameter as a command, and the
rest using default completion (files)?
I've tried "compctl -x 'p[1]' -c -- beroot", which does work for the
1st argument, but doesn't apply default completion to the other
arguments.
Any suggestions?
TIA,
Steve
~~
stephen.talley@central.sun.com
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: complete question
1997-04-14 20:12 complete question Steve Talley
@ 1997-04-14 21:54 ` blaise
0 siblings, 0 replies; 2+ messages in thread
From: blaise @ 1997-04-14 21:54 UTC (permalink / raw)
To: zsh-users
Steve Talley writes:
> I have a command "beroot" that executes any arguments as root. i.e.
>
> % beroot id -a
>
> prints out:
>
> uid=0(root) gid=10(staff) groups=10(staff),14(sysadmin)
>
> How can I get zsh to complete the first parameter as a command, and the
> rest using default completion (files)?
compctl -l '' beroot
--
Blaise Tarr
btarr@attmail.com
^ permalink raw reply [flat|nested] 2+ messages in thread
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1997-04-14 20:12 complete question Steve Talley
1997-04-14 21:54 ` blaise
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