why does this exit = 1 ?

why does this exit = 1 ?

[Timothy J Luoma]

I have this little snippet:

if [ -r /LocalLibrary/Images/Icons/tempPark.tiff -a ! -r /tmp/.dir.tiff ] then   
         ln -s /LocalLibrary/Images/Icons/tempPark.tiff /tmp/.dir.tiff

fi

When I run it and there is already a /tmp/.dir.tiff it exits = 1

I am curious why it does that, since there shouldn't be any 'error' --- or  
am I missing something?

TjL

Re: why does this exit = 1 ?

[Michael Barnes]

The if statement returns false so the script returns false (1),
if you want the script to return true just add exit 0 at the end.

Mike

On Sun, 5 Apr 1998, Timothy J Luoma wrote:

> 
> I have this little snippet:
> 
> if [ -r /LocalLibrary/Images/Icons/tempPark.tiff -a ! -r /tmp/.dir.tiff ] then   
>          ln -s /LocalLibrary/Images/Icons/tempPark.tiff /tmp/.dir.tiff
> 
> fi
> 
> When I run it and there is already a /tmp/.dir.tiff it exits = 1
> 
> I am curious why it does that, since there shouldn't be any 'error' --- or  
> am I missing something?
> 
> TjL
> 
> 
> 

Re: why does this exit = 1 ?

[C. v. Stuckrad]

strange thou, it works for me, tested it in a zsh-function!
I did

try() {
 if [ ! -r ... ]
 then echo no file
 fi
}

and tested with 'try; echo $?'

and file or no file the result was 0
(on zsh or sh;  Sun or LINUX(where sh==bash)

So what does happen really ?

Stucki

On Sun, 5 Apr 1998, Michael Barnes wrote:

> Subject: Re: why does this exit = 1 ?
> Date: Sun, 5 Apr 1998 04:22:20 -0400 (EDT)
> 
> The if statement returns false so the script returns false (1),
> if you want the script to return true just add exit 0 at the end.
...
> On Sun, 5 Apr 1998, Timothy J Luoma wrote:
> > I have this little snippet:
> > ...
> > if [ -r /LocalLibrary/Images/Icons/tempPark.tiff -a ! -r /tmp/.dir.tiff ] then   
> >          ln -s /LocalLibrary/Images/Icons/tempPark.tiff /tmp/.dir.tiff
> > fi
> > 
> > When I run it and there is already a /tmp/.dir.tiff it exits = 1


Christoph von Stuckrad       * *  | talk to  | <stucki@math.fu-berlin.de> \
Freie Universitaet Berlin    |/_* | nickname | ...!unido!fub!leibniz!stucki|
Fachbereich Mathematik, EDV  |\ * | 'stucki' | Tel:+49 30 838-75459        |
Arnimallee 2-6/14195 Berlin  * *  |  on IRC  | Fax:+49 30 838-75454       /

Re: why does this exit = 1 ?

[Bart Schaefer]

This has been sitting in my mailbox for a few days ...

On Apr 5,  4:27pm, C. v. Stuckrad wrote:
} Subject: Re: why does this exit = 1 ?
}
} strange thou, it works for me, tested it in a zsh-function!
} 
} So what does happen really ?
} 
} > On Sun, 5 Apr 1998, Timothy J Luoma wrote:
} > > I have this little snippet:
} > > ...
} > > if [ -r /LocalLibrary/Images/Icons/tempPark.tiff -a ! -r /tmp/.dir.tiff ] then   
} > >          ln -s /LocalLibrary/Images/Icons/tempPark.tiff /tmp/.dir.tiff
} > > fi
} > > 
} > > When I run it and there is already a /tmp/.dir.tiff it exits = 1

Two guesses:

1.  It's the alias-for-fi problem again, but something else is masking the
    syntax error.

2.  /tmp/.dir.tiff exists but is not readable, so [ ! -r /tmp/.dir.tiff ]
    succeeds but ln fails.  Try [ ! -f /tmp/.dir.tiff ].

-- 
Bart Schaefer                                 Brass Lantern Enterprises
http://www.well.com/user/barts              http://www.brasslantern.com