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Date: Fri, 18 Mar 2011 15:32:43 +0100
Message-ID: <AANLkTimBkrj=PFb4XTdNarrnH=0nKERw-JTxQ3HcZ0GQ@mail.gmail.com>
Subject: Re: A hyphen bug or not?
From: Mikael Magnusson <mikachu@gmail.com>
To: nix@myproxylists.com
Cc: zsh-users@zsh.org
Content-Type: text/plain; charset=UTF-8

On 18 March 2011 15:15,  <nix@myproxylists.com> wrote:
> #!/bin/zsh
>
> emulate zsh
>
> R="-"
>
> echo "$R" # <--- its empty here as well !
>
> R=$(echo "$R" | base64)
> R=$(print ${R//$'\n'})
>
> echo "R: $R" # <--- this is wrong, it should be a hyphen -
>
> # When we change the "R" variable to a octal presentation of hyphen
>
> R="\055"
> R=$(echo "$R" | base64)
> R=$(print ${R//$'\n'})
>
> echo "R: $R" # <--- now it works and base64 decod returns a hyphen "-" as
> it should.
>
>
> How I can echo a hyphen without echoing octal?

Your problem is that echo actually interprets options, if you want to
echo arguments starting with a hyphen you should use echo - "arguments
here" (it's always safe to add the leading hyphen to separate options
from arguments). If you also don't want to interpret escapes, use echo
-E - "arguments here".

-- 
Mikael Magnusson