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From: Bart Schaefer <schaefer@brasslantern.com>
To: "Benjamin R. Haskell" <zsh@benizi.com>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: Assign to parameter in parameter -- opposite of ${(P)name}?
Date: Sat, 10 Jul 2010 10:39:37 -0700	[thread overview]
Message-ID: <AANLkTinb3yaEmTkDQu0g_NOuJnm5-KWMdK_FK-toGMeX@mail.gmail.com> (raw)
In-Reply-To: <alpine.LNX.2.01.1007091908420.4808@hp.internal>

On Fri, Jul 9, 2010 at 4:17 PM, Benjamin R. Haskell <zsh@benizi.com> wrote:
> It's the end of the week, and I'm tired, so I'm sure I'm completely
> overlooking something obvious, but how do you *assign* to a parameter
> whose name is in a parameter?

Your first attempt wasn't complicated enough, but your second attempt
was too complicated. :-)

% name=foo
% : ${(P)name::=something}
% print $foo
something
% print $name
foo

The (P)name is interpreted before the ::= so you don't need nested expansion.


      parent reply	other threads:[~2010-07-10 17:39 UTC|newest]

Thread overview: 8+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2010-07-09 23:17 Benjamin R. Haskell
2010-07-10  1:13 ` Frank Terbeck
2010-07-10 15:36   ` Benjamin R. Haskell
2010-07-10 15:44     ` Frank Terbeck
2010-07-10 15:54       ` Benjamin R. Haskell
2010-07-10 14:57 ` Julius Plenz
2010-07-10 15:52   ` Benjamin R. Haskell
2010-07-10 17:39 ` Bart Schaefer [this message]

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