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Subject: Re: ${var:1:1:=y}
From: =?utf-8?Q?Lawrence_Vel=C3=A1zquez?= <vq@larryv.me>
In-Reply-To: <54D16A4C.9010609@eastlink.ca>
Date: Tue, 3 Feb 2015 20:30:26 -0500
Cc: zsh-users@zsh.org
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References: <54D155C8.4080600@eastlink.ca> <412544FB-49A2-43AA-BC76-DC1AF1AA71BE@larryv.me> <54D16A4C.9010609@eastlink.ca>
To: Ray Andrews <rayandrews@eastlink.ca>
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On Feb 3, 2015, at 7:39 PM, Ray Andrews <rayandrews@eastlink.ca> wrote:

> I'd naively read it: assign to 'variable' either the value of the =
second character of 'var' (just one character), and if that does not =
exist, assign 'y'.

See, that interpretation didn't occur to me at all :)

=46rom zshexpn(1):

    If a ${...} type parameter expression or a $(...) type command
    substitution is used in place of "name" above, it is expanded first
    and the result is used as if it were the value of "name".

So you'd probably want something like this, except with variable
assignment instead of `echo`:

    % foo=3D
    % echo ${${foo:1:1}:-y}
    y
    % foo=3Da
    % echo ${${foo:1:1}:-y}
    y
    % foo=3Dabcdef
    % echo ${${foo:1:1}:-y}
    b
    %

vq=