Re: Substituting grep (and other) output to open files in Vim

[Mikael Magnusson <mikachu@gmail.com>]

On 10 May 2011 15:46, Richard Hartmann <richih.mailinglist@gmail.com> wrote:
> Hi all,
>
> I would like to be able to do the following, but I am stuck. Every
> pair of lines is what I would execute and what it would be transferred
> to. I am assuming that every file "name" (i.e. including colons etc) I
> am running Vim on does not exist. If it exists, it should be opened
> instead of magic happening. "foo" exists while "foo:" etc do not.
>
> vim foo:
> vim foo
>
> vim foo:bar
> vim foo
>
> vim foo:123
> vim foo +123
>
> vim foo:123:
> vim foo +123
>
> vim foo:123:bar
> vim foo +123
>
> Ideally, the same would happen for vimdiff. And yes, vimdiff heeds
> only one +n and the last one on the command line wins. That's fine.
>
>
> I am pretty sure this is trivial to do in zsh, but as I said I am at a
> loss as to how..
>
>
> Thanks,
> Richard
>

This only does the foo:123: case, but you should be able to adapt it,
	if [[ $1 =~ ^(.*[^/]):([0-9]+):$ ]]; then
		1=$match[1]
		2=+$match[2]
	fi

I also have a non-regex version commented out, it is arguably less readable,
	if [[ $1 = *[^/]##:(#b)([0-9]##)(#B): ]]; then
		2=+${1[$mbegin[1],$mend[1]]}
		1=${1[1,$mbegin[1]-2]}
	fi

Ahead of this you'll want to check test -f $1 to avoid munging the
argument if the file exists.

Changing the regex to ^(.*[^/]):([0-9]+)[^0-9].*$ should cover two of
your other cases, but you might want to be more restrictive than .*
there, not sure what you want to allow bar to be.

-- 
Mikael Magnusson