From: "Jérémie Roquet" <arkanosis@gmail.com>
To: zsh-users@zsh.org
Cc: Richard Hartmann <richih.mailinglist@gmail.com>
Subject: Re: Substituting grep (and other) output to open files in Vim
Date: Tue, 10 May 2011 16:14:01 +0200 [thread overview]
Message-ID: <BANLkTik0-EfNso_Qu_rHZBS=6z_Zo9cs_g@mail.gmail.com> (raw)
In-Reply-To: <BANLkTik+65NedRoVNJMgj9+Oma_XDmz8dA@mail.gmail.com>
Hi Richard,
2011/5/10 Richard Hartmann <richih.mailinglist@gmail.com>:
> I would like to be able to do the following, but I am stuck. Every
> pair of lines is what I would execute and what it would be transferred
> to. I am assuming that every file "name" (i.e. including colons etc) I
> am running Vim on does not exist. If it exists, it should be opened
> instead of magic happening. "foo" exists while "foo:" etc do not.
>
> vim foo:
> vim foo
>
> vim foo:bar
> vim foo
>
> vim foo:123
> vim foo +123
>
> vim foo:123:
> vim foo +123
>
> vim foo:123:bar
> vim foo +123
>
> Ideally, the same would happen for vimdiff. And yes, vimdiff heeds
> only one +n and the last one on the command line wins. That's fine.
>
>
> I am pretty sure this is trivial to do in zsh, but as I said I am at a
> loss as to how..
Something like
vim() {
if test -r $1; then
command vim $1
else
args=(${(s.:.)1})
[[ $args[2] = <-> ]] && command vim $args[1] +$args[2] || command
vim $args[1]
fi
}
?
Best regards,
--
Jérémie
next prev parent reply other threads:[~2011-05-10 14:20 UTC|newest]
Thread overview: 13+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-05-10 13:46 Richard Hartmann
2011-05-10 14:12 ` Mikael Magnusson
2011-05-10 14:14 ` Jérémie Roquet [this message]
2011-05-10 18:16 ` Richard Hartmann
2011-05-11 1:00 ` Wayne Davison
2011-05-27 15:09 ` Richard Hartmann
2011-05-27 22:00 ` Wayne Davison
2011-05-28 11:51 ` Richard Hartmann
2011-05-10 15:26 ` Benjamin R. Haskell
2011-05-10 17:37 ` Mikael Magnusson
2011-05-10 18:16 ` Richard Hartmann
2011-05-10 18:58 ` Benjamin R. Haskell
2011-05-10 22:27 ` Richard Hartmann
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