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From: Pablo Lalloni <plalloni@gmail.com>
Date: Sun, 18 Dec 2016 20:02:29 -0300
Message-ID: <CAAiKvi0Ge4-9016srG4K5-3-VnwCXN5FcKtsjGtE6GjG8ZwGsA@mail.gmail.com>
Subject: Apparent inconsistency in f/z expansion flags behavior
To: zsh-users@zsh.org
Content-Type: multipart/alternative; boundary=001a114115b6853ce80543f6ce41

--001a114115b6853ce80543f6ce41
Content-Type: text/plain; charset=UTF-8

Hello there!

I'm seeing an unexpected (to me) difference in the behavior of these flags.

Say you do something like:

words=(${(z)$(</proc/meminfo)})

Which set words with the array of all the words in the file and that's
great.

Then I try the f flag in place of z, expecting to get an array with the
file's lines:

lines=(${(f)$(</proc/meminfo)})

But then I get an array with just one string containing all the lines
concatenated (no NLs).

So... Is this expected? What I need to do to get the array of lines?

Note that if you split the last assignment in 2 steps, it works as expected:

lines=$(</proc/meminfo)
lines=(${(f)lines})

Which is ok, but of course anybody would want to do it in one step, right?

Cheers!

--001a114115b6853ce80543f6ce41--