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Date: Thu, 13 Feb 2014 08:17:58 +0100
Message-ID: <CABABwVH+Yu-oFiE8OYkmNHxRGSwfYT8331oA0=0s9quom3CTGA@mail.gmail.com>
Subject: zparseopts default associative array
From: Sebastian Stark <seb.stark@gmail.com>
To: zsh-users@zsh.org
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Hi,

if I have this script:

  typeset -A o
  o=(-a AAA -b BBB)
  zparseopts -K -A o a: b:
  print -- ${(kv)o[@]}

and run it such:

  ./script.sh -a foo

I would expect it to output "-a foo -b BBB". But the output is "-a
foo". In the manual the -K option to zparseopts is described as this:

"  -K     With this option, the arrays specified with the -a and -A
options and with the `=array' forms are kept unchanged when none of
the specs for them is used.  This  allows  assignment of default
values to them before calling zparseopts."

Maybe I misunderstood something, but isn't my example the intended use
of -K? Or is the condition "when none of the specs for them is used"
really meant like "if one option is given, all other default values
are emptied"? How would this make sense?

I tried with zsh versions 5.0.2 and 4.3.10.


Sebastian