From: "Jesper Nygårds" <jesper.nygards@gmail.com>
To: Zsh Users <zsh-users@zsh.org>
Subject: Filtering array on index
Date: Thu, 25 Oct 2018 13:29:01 +0200 [thread overview]
Message-ID: <CABZhJg80vQuMHGKABkzR1bdtt89Akpkfd8kWOV83N-qvqioaXw@mail.gmail.com> (raw)
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I have an array which is the result of using zparseopts on a specification
that makes it possible to specify several filters with a -v flag. The
resulting array might look like the following:
myarr=(-v filter1 -v filter2)
I want to get rid of the "-v" elements, but only when they are the flag,
and not the argument. In other words, I would the like the array (-v
filter1 -v -v) to result in (filter1 -v).
I had previously used:
${myarr:#-v}}
which worked well, as I could accept the fact that -v was not possible to
use as the option argument.
However, now I need to make sure that a -v argument is preserved, and I
thus need a compact way of specifying that I want to keep every other
element in the array.
The most compact way I have found is:
for dash arg in $myarr; do myarr[(r)$dash]=()
This works, but I was wondering if there's some more elegant solution,
preferrably without using iteration?
next reply other threads:[~2018-10-25 11:29 UTC|newest]
Thread overview: 15+ messages / expand[flat|nested] mbox.gz Atom feed top
2018-10-25 11:29 Jesper Nygårds [this message]
2018-10-25 18:17 ` Mikael Magnusson
2018-10-25 18:55 ` Jesper Nygårds
2018-10-25 19:42 ` Daniel Shahaf
2018-10-25 20:21 ` Bart Schaefer
2018-10-25 20:42 ` dana
2018-10-26 4:14 ` Jesper Nygårds
2018-10-26 7:59 ` Jesper Nygårds
2018-10-26 8:21 ` dana
2018-10-26 9:28 ` Jesper Nygårds
2018-10-28 2:45 ` Bart Schaefer
2019-07-23 3:38 ` Sebastian Gniazdowski
2019-07-23 7:42 ` Sebastian Gniazdowski
2019-07-23 8:03 ` Sebastian Gniazdowski
2019-09-08 8:59 ` Sebastian Gniazdowski
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