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From: =?UTF-8?Q?Jesper_Nyg=C3=A5rds?= <jesper.nygards@gmail.com>
Date: Wed, 31 Oct 2018 09:19:30 +0100
Message-ID: <CABZhJg8F_5WLoAmvgUVMwDfkCV36h+S1uQ06j4cn1jndNLqjHQ@mail.gmail.com>
Subject: Printing empty array elements
To: Zsh Users <zsh-users@zsh.org>
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Consider the following:

% rlines=("${(@f)$(print a; print; print c)}")

% for (( i=1; $i<=$#rlines; i+=1 )); do print $rlines[$i]; done
a

c

% print -l $rlines
a
c

In other words, "print -l" doesn't print empty array elements (or perhaps
it never even sees them?). Is there a way to make it not omit empty
elements when printing an array, apart from iterating over the elements?

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