Printing empty array elements

Printing empty array elements

[Jesper Nygårds]

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Consider the following:

% rlines=("${(@f)$(print a; print; print c)}")

% for (( i=1; $i<=$#rlines; i+=1 )); do print $rlines[$i]; done
a

c

% print -l $rlines
a
c

In other words, "print -l" doesn't print empty array elements (or perhaps
it never even sees them?). Is there a way to make it not omit empty
elements when printing an array, apart from iterating over the elements?

Re: Printing empty array elements

[Jesper Nygårds]

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Aargh. Twenty years of shell programming, and still I'm making rookie
mistakes when it comes to quoting. The answer is of course:

% print -l "$rlines[@]"

Re: Printing empty array elements

[Mikael Magnusson]

On 10/31/18, Jesper Nygårds <jesper.nygards@gmail.com> wrote:
> Aargh. Twenty years of shell programming, and still I'm making rookie
> mistakes when it comes to quoting. The answer is of course:
>
> % print -l "$rlines[@]"

You can also use "${(@)rlines}" as in the first line of your code
(which is also necessary if you want to use a subscript range).

-- 
Mikael Magnusson

Re: Printing empty array elements

[Jesper Nygårds]

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On Wed, Oct 31, 2018 at 11:00 AM Mikael Magnusson <mikachu@gmail.com> wrote:

> You can also use "${(@)rlines}" as in the first line of your code
> (which is also necessary if you want to use a subscript range).


 Thank you, that's a great tip. Didn't see the connection.