From: "Jesper Nygårds" <jesper.nygards@gmail.com>
To: Zsh Users <zsh-users@zsh.org>
Subject: Re: A minor syntax question
Date: Tue, 7 Jun 2016 20:47:28 +0200 [thread overview]
Message-ID: <CABZhJg_2smdBcCcDa86fBB1Xw1DWCxpWBcCNwcxoCeMM7an9gQ@mail.gmail.com> (raw)
In-Reply-To: <26949.1465300483@thecus.kiddle.eu>
[-- Attachment #1: Type: text/plain, Size: 1070 bytes --]
Both your examples work great, Oliver. Thank you.
Inspired by your second example I also found a solution which more closely
follows the way I have been thinking about the problem, and that I find
quite readable:
typearg="("${(j: -o :)${types:#-t}/#/-type }")"
On Tue, Jun 7, 2016 at 1:54 PM, Oliver Kiddle <okiddle@yahoo.co.uk> wrote:
> Jesper Nygårds wrote:
> > typearg="("${"$(print -- '-o -type '${^types:#-t})"#-o }")"
>
> > away the leading '-o'. It works as intended, but I feel it is more
> > complicated than required. In particular, I couldn't find a way to make
> the
> > '${^...}' parameter expansion trigger without the embedded print
> statement.
>
> Joining the array to form a string should avoid the need for a print,
> allowing the #-o to apply to the string as a whole. E.g:
>
> typearg=${${(j. .):-'-o -type '${^types:#-t}}#-o }
>
> Shorter versions should be possible such as the following:
>
> typearg="${${=types//-t/-o -type}[2,-1]}"
>
> I'd be inclined to keep typearg as an array, however.
>
> Oliver
>
prev parent reply other threads:[~2016-06-07 18:47 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2016-06-07 6:58 Jesper Nygårds
2016-06-07 11:54 ` Oliver Kiddle
2016-06-07 18:47 ` Jesper Nygårds [this message]
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