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From: Kurtis Rader <krader@skepticism.us>
To: Thorsten Kampe <thorsten@thorstenkampe.de>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: `[[ -n $VAR ]]` equal to `[[ $VAR ]]`?
Date: Thu, 9 Apr 2015 18:31:04 -0700	[thread overview]
Message-ID: <CABx2=D-VTpp3ihAE_A2KCdE3tcPu5RPuB8WJwtv-G=B0QNx0GQ@mail.gmail.com> (raw)
In-Reply-To: <mg78mg$vqb$1@ger.gmane.org>

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When I run the following

    [[ $VAR ]] && print yes

I get a parse error. Which is what I expected given the documentation in
section "Conditional Expressions" of "man zshall". Are you seeing different
behavior? What makes you think a bare variable is a valid expression?

On Thu, Apr 9, 2015 at 6:23 PM, Thorsten Kampe <thorsten@thorstenkampe.de>
wrote:

> Hi,
>
> this is kind of a follow-up to
> http://www.zsh.org/mla/users/2011/msg00284.html .
>
> Basically the solutions were `((+VAR))` for zsh and `[[ -n
> ${VAR+stuff} ]]` for bash and zsh.
>
> Now my question is, isn't `[[ -n $VAR ]]` equivalent to `[[ $VAR ]]`?
> (`[[ -n ${VAR+stuff} ]]` equivalent to `[[ ${VAR+stuff} ]]`)
>
> Thorsten
>
>


-- 
Kurtis Rader
Caretaker of the exceptional canines Junior and Hank

  reply	other threads:[~2015-04-10  1:31 UTC|newest]

Thread overview: 16+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2015-04-10  1:23 Thorsten Kampe
2015-04-10  1:31 ` Kurtis Rader [this message]
2015-04-10  1:39   ` Thorsten Kampe
2015-04-10  2:02     ` Kurtis Rader
2015-04-10  2:05       ` Kurtis Rader
2015-04-10  2:46         ` Mikael Magnusson
2015-04-10  2:59           ` Kurtis Rader
2015-04-10  4:00             ` Mikael Magnusson
2015-04-10  6:06             ` Thorsten Kampe
2015-04-13 16:52               ` Ray Andrews
2015-04-13 17:36                 ` Roman Neuhauser
2015-04-13 23:58                   ` Ray Andrews
2015-04-14  1:27                     ` Bart Schaefer
2015-04-14 15:06                       ` Ray Andrews
2015-04-10  3:21           ` Kurtis Rader
2015-04-10  2:01 ` Bart Schaefer

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