From: "Damien Thébault" <damien.thebault@gmail.com>
To: zsh-users@zsh.org
Subject: Re: Why the l parameter flag in this case not work?
Date: Tue, 20 Mar 2012 09:57:08 +0100 [thread overview]
Message-ID: <CAEcrOvCsRGsfvCO_n6HfkjG=_REbGuu4nCTbb+zZK7w+_2o+xw@mail.gmail.com> (raw)
In-Reply-To: <20120320083214.GA3818@lilyforest>
On Tue, Mar 20, 2012 at 09:32, lilydjwg <lilydjwg@gmail.com> wrote:
> I tried to print a line of `-' but not work:
>
> print ${(l.80..-.)}
>
> An empty line is printed. However, printing a line of `=' or other
> strings do work:
>
> print ${(l.80..+.)}
>
> I tried to quote `-', but only 40 `-'s are printed:
>
> print ${(l.80..\-.)}
>
The "print" command is intepreting the expanded expression as an
argument, you can use "echo" or use "--" to tell the "print" command
that the end of arguments has been reached:
echo ${(l.80..-.)}
print -- ${(l.80..-.)}
Regards,
--
Damien Thebault
next prev parent reply other threads:[~2012-03-20 8:57 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2012-03-20 8:32 lilydjwg
2012-03-20 8:57 ` Damien Thébault [this message]
2012-03-20 13:41 ` lilydjwg
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