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In-Reply-To: <20120320083214.GA3818@lilyforest>
References: <20120320083214.GA3818@lilyforest>
Date: Tue, 20 Mar 2012 09:57:08 +0100
Message-ID: <CAEcrOvCsRGsfvCO_n6HfkjG=_REbGuu4nCTbb+zZK7w+_2o+xw@mail.gmail.com>
Subject: Re: Why the l parameter flag in this case not work?
From: =?UTF-8?Q?Damien_Th=C3=A9bault?= <damien.thebault@gmail.com>
To: zsh-users@zsh.org
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On Tue, Mar 20, 2012 at 09:32, lilydjwg <lilydjwg@gmail.com> wrote:
> I tried to print a line of `-' but not work:
>
> print ${(l.80..-.)}
>
> An empty line is printed. However, printing a line of `=' or other
> strings do work:
>
> print ${(l.80..+.)}
>
> I tried to quote `-', but only 40 `-'s are printed:
>
> print ${(l.80..\-.)}
>

The "print" command is intepreting the expanded expression as an
argument, you can use "echo" or use "--" to tell the "print" command
that the end of arguments has been reached:

echo ${(l.80..-.)}
print -- ${(l.80..-.)}

Regards,
-- 
Damien Thebault