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From: "Jérémie Roquet" <jroquet@arkanosis.net>
To: TJ Luoma <luomat@gmail.com>
Cc: Zsh MailingList <zsh-users@zsh.org>
Subject: Re: completion for function arguments?
Date: Thu, 8 Aug 2019 15:49:52 +0200	[thread overview]
Message-ID: <CAFOazAM-Md+1QFyYSgEeoGCFgz5_-nD40s_01f28vDdhSQfL0A@mail.gmail.com> (raw)
In-Reply-To: <CADjGqHu2c=s8wk_wkrMEX4OdJOtWTNuCDnBynXgESYhjBiNdBQ@mail.gmail.com>

Le jeu. 8 août 2019 à 15:08, TJ Luoma <luomat@gmail.com> a écrit :
> Let me start by saying that I don't understand completion at all,

So, let's start by saying that I don't understand them much either,
and that someone will probably suggest something much simpler using
zstyle.

> I have a function called 'jump' which I will include below.
> The function takes one (1) argument from a specific list of arguments.

The following should work:

_jump() {
  local targets=(macbook imac tyrion)
  _wanted jump_target expl 'Jump target' compadd -a targets
}
compdef  _jump jump

Note that you can achieve the same effect by just putting the
following in a file named _jump somewhere in your $fpath:

#compdef jump
local targets=(macbook imac tyrion)
_wanted jump_target expl 'Jump target' compadd -a targets

As I said, it should work, but there are probably much nicer ways to
achieve the same result.

Best regards,

-- 
Jérémie

  reply	other threads:[~2019-08-08 13:51 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2019-08-08 13:06 TJ Luoma
2019-08-08 13:49 ` Jérémie Roquet [this message]
2019-08-08 15:42 ` Mikael Magnusson

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