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Sun, 05 Feb 2023 21:04:10 -0800 (PST) MIME-Version: 1.0 References: In-Reply-To: From: Bart Schaefer Date: Sun, 5 Feb 2023 21:03:59 -0800 Message-ID: Subject: Re: why is (F) about twice as fast as print -l ? To: sergio Cc: zsh-users@zsh.org Content-Type: text/plain; charset="UTF-8" X-Seq: 28905 Archived-At: X-Loop: zsh-users@zsh.org Errors-To: zsh-users-owner@zsh.org Precedence: list Precedence: bulk Sender: zsh-users-request@zsh.org X-no-archive: yes List-Id: List-Help: , List-Subscribe: , List-Unsubscribe: , List-Post: List-Owner: List-Archive: On Sun, Feb 5, 2023 at 8:15 PM sergio wrote: > > l=({1..100000000}) ${(F)l} joins this huge array into a single string and then that single argument is passed to "print". print -l $l expands the array and passes all those words to "print", requiring that they individually be copied at least one extra time. Incidentally, print -aC1 $l is even slower, but printf "%s\n" $l is about the same as print -l.