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From: Bart Schaefer <schaefer@brasslantern.com>
To: Zach Riggle <zachriggle@gmail.com>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: zoptargs usage to place multiple values into an array
Date: Thu, 29 Sep 2022 15:54:06 -0700	[thread overview]
Message-ID: <CAH+w=7aVpS6i1rf8us2yeo_+uuPGZJis-xK0tAPqMdW4Qm+fEQ@mail.gmail.com> (raw)
In-Reply-To: <CAMP9c5ntpj_+RDnj-rbr1aur4AjeoJuP5Ghb8A4eU1Mtk9doDQ@mail.gmail.com>

On Wed, Sep 28, 2022 at 3:01 PM Zach Riggle <zachriggle@gmail.com> wrote:
>
> I know this is in the documentation, but what is the incantation to
> zoptargs to permit multiple command line **values**?

You mean zparseopts?  OPTARG is a variable used by the getopts builtin.

> Desired CLI:
>
>         $ ./script.zsh --arg value1 --arg value2 --arg value3
>
> Desired effect in script:
>
>         declare -a arg=( value1 value2 value3 )

You can't get that directly. If you use

zparseopts - -arg+:=arg

Then you get

arg=(--arg value1 --arg value2 --arg value3)

from which you have to delete the "--arg" elements yourself, e.g.

arg=(${arg:#--arg})

Is that close enough?


      reply	other threads:[~2022-09-29 22:55 UTC|newest]

Thread overview: 2+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2022-09-28 22:01 Zach Riggle
2022-09-29 22:54 ` Bart Schaefer [this message]

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