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Tue, 02 Aug 2022 17:40:46 -0700 (PDT) MIME-Version: 1.0 References: <39BA2F80-DBD0-4626-A57D-58109078CFD5@gmail.com> In-Reply-To: <39BA2F80-DBD0-4626-A57D-58109078CFD5@gmail.com> From: Bart Schaefer Date: Tue, 2 Aug 2022 17:40:35 -0700 Message-ID: Subject: Re: Sed error To: Aki Hoji Cc: Zsh Users Content-Type: text/plain; charset="UTF-8" X-Seq: 27924 Archived-At: X-Loop: zsh-users@zsh.org Errors-To: zsh-users-owner@zsh.org Precedence: list Precedence: bulk Sender: zsh-users-request@zsh.org X-no-archive: yes List-Id: List-Help: List-Subscribe: List-Unsubscribe: List-Post: List-Owner: List-Archive: On Tue, Aug 2, 2022 at 5:12 PM Aki Hoji wrote: > > I get the error message (sed: -e expression #1, char 2: invalid usage of line address 0) when I run a following; > > parallel -a temp3.fq -k --block 50M --pipe-part 'sed -e "$!N;/\nXQ@A00165/!P;D"' > temp4.fq $! is the PID of the last background job. That's being expanded to 0 because the argument to -e is in double quotes, resulting in an expression starting with "0N;" In bash, $! expands to the empty string when there are no background jobs, rather than to zero. In that case the expression starts with "N;" which is also probably not what you meant, but isn't a sed error. You need to quote the expression so that the $! is not expanded. This might work: EXPR='$!N;/\nXQ@A00165/!P;D' parallel -a temp3.fq -k --block 50M --pipe-part 'sed -e "$EXPR"'