Re: numeric for-loop and string for-loop

[Mikael Magnusson <mikachu@gmail.com>]

% a=5+5 b=2\*3
% typeset -i i
% for i in a b; do declare -p i; done; declare -p a b
typeset -i i=10
typeset -i i=6
typeset a=5+5
typeset b='2*3'

If this is not what you want, you can use unset i before each loop.

On 12/3/18, Peng Yu <pengyu.ut@gmail.com> wrote:
> Hi,
>
> The following zsh and bash code generate different resutls. I feel the
> bash convention is better.
>
> To make the second i as string in zsh, what is the best solution so
> that the minimum amount of code is changed. (I'd rather not to change
> the second `i` to some other variable name as each for-loop should be
> independent from each other, and should not know each other to make
> the code work.). Thanks.
>
> $ cat main.sh
> #!/usr/bin/env zsh
> # vim: set noexpandtab tabstop=2:
>
> set -v
> for ((i=0;i<2;++i))
> do
>     echo $i
> done
>
> declare -p i
> for i in a b
> do
>     declare -p i
> done
>
>
> $ cat main.bash
> #!/usr/bin/env bash
> # vim: set noexpandtab tabstop=2:
>
> set -v
> for ((i=0;i<2;++i))
> do
>     echo $i
> done
>
> declare -p i
> for i in a b
> do
>     declare -p i
> done
>
>
> $ ./main.sh
> for ((i=0;i<2;++i))
> do
>     echo $i
> done
> 0
> 1
>
> declare -p i
> typeset -i i=2
> for i in a b
> do
>     declare -p i
> done
> typeset -i i=0
> typeset -i i=0
>
>
> $ ./main.bash
> for ((i=0;i<2;++i))
> do
>     echo $i
> done
> 0
> 1
>
> declare -p i
> declare -- i="2"
> for i in a b
> do
>     declare -p i
> done
> declare -- i="a"
> declare -- i="b"
>
> --
> Regards,
> Peng
>


-- 
Mikael Magnusson