It seems that it's / within the '-quoted string that causes the problem:

print ${QE//'0=${${(M)${0::=${(%):-%x}}:#\/*}:-$PWD\/$0}'/°match°}

outputs °match°, while:

print ${QE//'0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'/°match°}

doesn't. Isn't it a bug of ignoring '-quoting of /?


On Wed, 25 Jan 2023 at 12:59, Sebastian Gniazdowski <sgniazdowski@gmail.com>
wrote:

> Ok, I'll take a closer look, however I'm now struggling with similar
> problem:
>
> QE='0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'
> print ${QE//'0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'/°match°}
>
> the strings in QE and in …//'…'/… are identical. Why no match? A simpler
> example works as expected:
>
> QE=qeqe
> print ${(S)QE//'qeqe'/°match°}
>
> Output:
>
> °match°
>
> On Wed, 25 Jan 2023 at 12:36, Roman Perepelitsa <
> roman.perepelitsa@gmail.com> wrote:
>
>> On Wed, Jan 25, 2023 at 12:05 PM Sebastian Gniazdowski
>> <sgniazdowski@gmail.com> wrote:
>> >
>> > Hi,
>> > I'm storing a pattern in a var:
>> >
>> > E="0='\${\${\\(M\\)\${0::=\${\\(%\\):-%x}}:\\#/\\*}:-\$PWD/\$0}'"
>> >
>> > to then match it against:
>> >
>> > Q='0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'
>> >
>> > with // substitution:
>> >
>> > printf %s\\n $E $Q ${Q//$~E/q}
>> >
>> > The result is no match. However, if I instead quote the string with \:
>> >
>> > E='0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}'
>>
>> You can print them to see the difference:
>>
>>     % E="0='\${\${\\(M\\)\${0::=\${\\(%\\):-%x}}:\\#/\\*}:-\$PWD/\$0}'"
>>     % print -r -- $E
>>     0='${${\(M\)${0::=${\(%\):-%x}}:\#/\*}:-$PWD/$0}'
>>
>>     % E='0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}'
>>     % print -r -- $E
>>     0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}
>>
>> As you can see, the first `E` has three extra characters: two quotes
>> and a backslash.
>>
>> Roman.
>>
>
>
> --
> Best regards,
> Sebastian Gniazdowski
>
>

-- 
Best regards,
Sebastian Gniazdowski