Re: Mysterious (debug?) output in loop

[Sebastian Gniazdowski <sgniazdowski@gmail.com>]

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You can find some other useful options here:
https://zdharma-continuum.github.io/Zsh-100-Commits-Club/Zsh-Plugin-Standard.html#std-options

niedz., 29 sty 2023, 21:19 użytkownik Dominik Vogt <dominik.vogt@gmx.de>
napisał:

> Running this script
>
> --- snip ---
> #!/usr/bin/zsh
> emulate zsh
> repeat 3; do
>         local FOO
>         FOO="0"
> done
> --- snip ---
>
> Produces this output:
>
>   $ ./foo
>   FOO=0
>   FOO=0
>
>   $ zsh --version
>   zsh 5.8 (x86_64-debian-linux-gnu)
>
> Why does it print 'FOO=0' to stdout (not stderr) in all passes of
> the loop except the first one?  Is that some forgotten debug
> output?  Is there a way to disable that (without writing the
> script in a different way)?
>
> Of course I'm aware that (a) using local variables in global scope
> is useless and (b) variables are local to functions, not local to
> loops.  Before stripping down the test case, it was some code in a
> function.  Moving 'local FOO' out of the loop, or replacing it
> with 'local FOO="0"' suppresses the output.
>
> Ciao
>
> Dominik ^_^  ^_^
>
> --
>
> Dominik Vogt
>
>

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