Ok, I'll take a closer look, however I'm now struggling with similar
problem:

QE='0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'
print ${QE//'0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'/°match°}

the strings in QE and in …//'…'/… are identical. Why no match? A simpler
example works as expected:

QE=qeqe
print ${(S)QE//'qeqe'/°match°}

Output:

°match°

On Wed, 25 Jan 2023 at 12:36, Roman Perepelitsa <roman.perepelitsa@gmail.com>
wrote:

> On Wed, Jan 25, 2023 at 12:05 PM Sebastian Gniazdowski
> <sgniazdowski@gmail.com> wrote:
> >
> > Hi,
> > I'm storing a pattern in a var:
> >
> > E="0='\${\${\\(M\\)\${0::=\${\\(%\\):-%x}}:\\#/\\*}:-\$PWD/\$0}'"
> >
> > to then match it against:
> >
> > Q='0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'
> >
> > with // substitution:
> >
> > printf %s\\n $E $Q ${Q//$~E/q}
> >
> > The result is no match. However, if I instead quote the string with \:
> >
> > E='0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}'
>
> You can print them to see the difference:
>
>     % E="0='\${\${\\(M\\)\${0::=\${\\(%\\):-%x}}:\\#/\\*}:-\$PWD/\$0}'"
>     % print -r -- $E
>     0='${${\(M\)${0::=${\(%\):-%x}}:\#/\*}:-$PWD/$0}'
>
>     % E='0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}'
>     % print -r -- $E
>     0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}
>
> As you can see, the first `E` has three extra characters: two quotes
> and a backslash.
>
> Roman.
>


-- 
Best regards,
Sebastian Gniazdowski