Ok, I'll take a closer look, however I'm now struggling with similar problem: QE='0=\${\${(M)\${0::=\${(%):-%x}}:#/*}:-\$PWD/\$0}' print \${QE//'0=\${\${(M)\${0::=\${(%):-%x}}:#/*}:-\$PWD/\$0}'/°match°} the strings in QE and in …//'…'/… are identical. Why no match? A simpler example works as expected: QE=qeqe print \${(S)QE//'qeqe'/°match°} Output: °match° On Wed, 25 Jan 2023 at 12:36, Roman Perepelitsa wrote: > On Wed, Jan 25, 2023 at 12:05 PM Sebastian Gniazdowski > wrote: > > > > Hi, > > I'm storing a pattern in a var: > > > > E="0='\\${\\${\\(M\\)\\${0::=\\${\\(%\\):-%x}}:\\#/\\*}:-\\$PWD/\\$0}'" > > > > to then match it against: > > > > Q='0=\${\${(M)\${0::=\${(%):-%x}}:#/*}:-\$PWD/\$0}' > > > > with // substitution: > > > > printf %s\\n \$E \$Q \${Q//\$~E/q} > > > > The result is no match. However, if I instead quote the string with \: > > > > E='0=\${\${\(M\)\${0::=\${\(%\):-%x}}:\#/*}:-\$PWD/\$0}' > > You can print them to see the difference: > > % E="0='\\${\\${\\(M\\)\\${0::=\\${\\(%\\):-%x}}:\\#/\\*}:-\\$PWD/\\$0}'" > % print -r -- \$E > 0='\${\${\(M\)\${0::=\${\(%\):-%x}}:\#/\*}:-\$PWD/\$0}' > > % E='0=\${\${\(M\)\${0::=\${\(%\):-%x}}:\#/*}:-\$PWD/\$0}' > % print -r -- \$E > 0=\${\${\(M\)\${0::=\${\(%\):-%x}}:\#/*}:-\$PWD/\$0} > > As you can see, the first `E` has three extra characters: two quotes > and a backslash. > > Roman. > -- Best regards, Sebastian Gniazdowski