Re: ${(z)} parsing of multiple array assignments

[Sebastian Gniazdowski <sgniazdowski@gmail.com>]

Looks like an empty assignment does reset the state for a single next one:

% x='a=(foo) b=() d=(bar)'
% print -rl -- "${(z)x}"
a=(
foo
)
b=
()
d=(
bar
)

On Tue, 24 Dec 2019 at 21:35, Phil Pennock
<zsh-workers+phil.pennock@spodhuis.org> wrote:
>
> On 2019-12-23 at 17:31 +0000, Daniel Shahaf wrote:
> > In the following two cases, why are the assignments to $b
> > parsed differently to the assignments to $a?
> >
> >     % pz() { print -rl -- ${(qqqq)${(z)1}} }
>
> Looks to be a bug, a lack of state reset.  In two places, perhaps: you
> can see that one example resets when you alternate back away from having
> empty assignment lists, where the b/c pairing here is reset by `d`, so
> that the f/g pairing matches.  But I can't trigger a reset to the
> initial parse state used for `a`; unless and until I introduce a
> newline, where in the second example you can see the same parse used for
> `e`:
>
>     % echo $ZSH_VERSION
>     5.7.1
>
>     % x='a=(foo) b=() c=() d=(bar) e=(baz) f=() g=()'
>     % print -rl -- "${(z)x}"
>     a=(
>     foo
>     )
>     b=
>     ()
>     c=(
>     )
>     d=(bar)
>     e=(baz)
>     f=
>     ()
>     g=(
>     )
>
>     ## differs in $'...' not '...' and \n between d and e:
>
>     % x=$'a=(foo) b=() c=() d=(bar)\ne=(baz) f=() g=()'
>     % print -rl -- "${(z)x}"
>     a=(
>     foo
>     )
>     b=
>     ()
>     c=(
>     )
>     d=(bar)
>     ;
>     e=(
>     baz
>     )
>     f=
>     ()
>     g=(
>     )
>


-- 
Sebastian Gniazdowski
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