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From: Sebastian Gniazdowski <sgniazdowski@gmail.com>
Date: Sat, 9 Nov 2019 10:09:44 +0100
Message-ID: <CAKc7PVCvXNx2R_sJsDAGW1vU_LKHRK5W_HDm496Efk0XpG9KzQ@mail.gmail.com>
Subject: Re: What's the reasoning behind z & s returning nular for empty input?
To: Roman Perepelitsa <roman.perepelitsa@gmail.com>
Cc: Zsh Users <zsh-users@zsh.org>
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On Sat, 9 Nov 2019 at 09:52, Roman Perepelitsa
<roman.perepelitsa@gmail.com> wrote:
>
> On Sat, Nov 9, 2019 at 9:40 AM Sebastian Gniazdowski
> <sgniazdowski@gmail.com> wrote:
> > Yes, I was also referring to this fragment, however it states that the
> > empty elements should be removed, and even =E2=80=93 that they should b=
e
> > removed more eagerly, so I still wonder why produce a nular for an
> > empty input?
>
> Oh, I see what you mean. Apparently, only inner empty elements are
> dropped by "${(s...)...}" while the first and the last are retained.
>
>     "${(s:,:):-a,,b}" =3D> (a b)
>     "${(s:,:):-,,}" =3D> ('' '')
>
> Looks like it's either a bug in the code or in the documentation.

True, I wasn't fully aware of that:

array=3D( "${(s:,:):-,,}" )
print -r ${(q)array}
Output:'' ''

array=3D( "${(s:,:):-,}" )
print -r ${(q)array}
Output:'' ''

I think that the documentation or the behavior should be updated.
--=20
Sebastian Gniazdowski
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