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From: Roman Perepelitsa <roman.perepelitsa@gmail.com>
To: Sebastian Gniazdowski <sgniazdowski@gmail.com>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: Why a '-quoted string isn't respected by // subst, while \-quoted is?
Date: Wed, 25 Jan 2023 13:36:34 +0100	[thread overview]
Message-ID: <CAN=4vMo6Aeia8P12-=-bh00xZnT9m7REMrMveRDSdUd9SMtfHQ@mail.gmail.com> (raw)
In-Reply-To: <CAKc7PVCm3sSqvnCT+aHHRpsKqFq93d7gtMLHD0-sEE7ZVZ-1gw@mail.gmail.com>

On Wed, Jan 25, 2023 at 12:05 PM Sebastian Gniazdowski
<sgniazdowski@gmail.com> wrote:
> Hi,
> I'm storing a pattern in a var:
> E="0='\${\${\\(M\\)\${0::=\${\\(%\\):-%x}}:\\#/\\*}:-\$PWD/\$0}'"
> to then match it against:
> Q='0=${${(M)${0::=${(%):-%x}}:#/*}:-$PWD/$0}'
> with // substitution:
> printf %s\\n $E $Q ${Q//$~E/q}
> The result is no match. However, if I instead quote the string with \:
> E='0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}'

You can print them to see the difference:

    % E="0='\${\${\\(M\\)\${0::=\${\\(%\\):-%x}}:\\#/\\*}:-\$PWD/\$0}'"
    % print -r -- $E

    % E='0=${${\(M\)${0::=${\(%\):-%x}}:\#/*}:-$PWD/$0}'
    % print -r -- $E

As you can see, the first `E` has three extra characters: two quotes
and a backslash.


  reply	other threads:[~2023-01-25 12:37 UTC|newest]

Thread overview: 7+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2023-01-25 11:04 Sebastian Gniazdowski
2023-01-25 12:36 ` Roman Perepelitsa [this message]
2023-01-25 12:59   ` Sebastian Gniazdowski
2023-01-25 13:09     ` Sebastian Gniazdowski
2023-01-25 13:10     ` Roman Perepelitsa
2023-01-27 18:43       ` Daniel Shahaf
2023-01-27 19:38         ` Bart Schaefer

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