From: Roman Perepelitsa <roman.perepelitsa@gmail.com>
To: Sebastian Gniazdowski <sgniazdowski@gmail.com>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: What's the reasoning behind z & s returning nular for empty input?
Date: Sat, 9 Nov 2019 08:50:46 +0100 [thread overview]
Message-ID: <CAN=4vMpj91iZzOgLNNcUzb4UuTDEAiFxkjyuAa76hqqaQjnFBg@mail.gmail.com> (raw)
In-Reply-To: <CAKc7PVCD7e=vATDBc7px1d4XNYiKu1=2iZP9YaJ5PutgsDTsoQ@mail.gmail.com>
On Sat, Nov 9, 2019 at 8:27 AM Sebastian Gniazdowski
<sgniazdowski@gmail.com> wrote:
>
> Hi
> arr=( "${(s:,:):-}" )
> print -r ${#arr} ${(q)arr}
> Output: 1 ''
This makes sense. Consider how many elements we should get when
splitting a string on commas:
split ",,," => 4 elements
split ",," => 3 elements
split "," => 2 elements
split "" => ???
The last split could give either 1 element or 0. The former is
consistent with the rest, the latter is not.
> arr=( "${(z):-}" )
> print -r ${#arr} ${(q)arr}
> Output: 1 ''
This is a bug IMO. Let's again consider how many elements we should
get when tokenizing different strings:
tokenize "a a a a" => 4 elements
tokenize "a a a" => 3 elements
tokenize "a a" => 2 elements
tokenize "a" => 1 element
tokenize "" => ???
Consistency requires that the last line gives zero elements. If it
gave one empty element, it would be the only case where (z) can
produce empty elements.
Here's another way to put it. For any array x,
"${(@z)${(j::)${(@q)x}}}" expands to "${(@q)x}", except when x is
empty. The special case is an inconsistency.
Roman.
next prev parent reply other threads:[~2019-11-09 7:51 UTC|newest]
Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top
2019-11-09 7:26 Sebastian Gniazdowski
2019-11-09 7:50 ` Roman Perepelitsa [this message]
2019-11-09 7:52 ` Roman Perepelitsa
2019-11-09 8:11 ` Sebastian Gniazdowski
2019-11-09 8:22 ` Roman Perepelitsa
2019-11-09 8:40 ` Sebastian Gniazdowski
2019-11-09 8:52 ` Roman Perepelitsa
2019-11-09 9:09 ` Sebastian Gniazdowski
2019-11-09 14:33 ` Peter Stephenson
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