From: Roman Perepelitsa <roman.perepelitsa@gmail.com>
To: Ray Andrews <rayandrews@eastlink.ca>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: coloring a substitution
Date: Tue, 8 Nov 2022 22:10:07 +0100 [thread overview]
Message-ID: <CAN=4vMqMsigw20xAdLGcTNmTVKWe4chtFRWLdcXdXS4zQR_Q2w@mail.gmail.com> (raw)
In-Reply-To: <5454df12-02c6-75b5-e552-c486e231183c@eastlink.ca>
On Tue, Nov 8, 2022 at 9:57 PM Ray Andrews <rayandrews@eastlink.ca> wrote:
>
> I'm seeing if I can make my function 100% zsh native. The 'sed' works.
> '$color' is just incrementing integers in a for loop starting at 31 (red):
>
> recent[$aa]=$( print $recent[$aa] | sed -r
> "s/$filter/\x1b\[$color;1m$filter\x1b\[0m/Ig" )
I'm assuming that:
- `print` is equivalent to `print -r --` here
- $filter doesn't have any metacharacters
- it's intentional that $filter is matched case-insensitively and
whatever matches is replaced literally by $filter
The last assumption looks the most weird to me and there is a chance
that this isn't what you intended the code to do.
> ... so I'm trying to get zsh string replacement to do the same job:
>
> recent[$aa]=${recent[$aa]/\x1b\[$color;1m$filter\x1b\[0m/}
Try this:
recent[$aa]=${recent[$aa]//(#i)$filter/$'\e['$color';1m'$filter$'\e[0m'}
Roman.
next prev parent reply other threads:[~2022-11-08 21:11 UTC|newest]
Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top
2022-11-08 20:56 Ray Andrews
2022-11-08 21:10 ` Roman Perepelitsa [this message]
2022-11-08 23:49 ` Ray Andrews
2022-11-09 0:11 ` Bart Schaefer
2022-11-09 0:32 ` Ray Andrews
2022-11-09 8:19 ` Roman Perepelitsa
2022-11-11 22:24 ` Ray Andrews
2022-11-11 22:39 ` Roman Perepelitsa
2022-11-12 3:36 ` Ray Andrews
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