From: Matt Zagrabelny <mzagrabe@d.umn.edu>
To: zsh-users@zsh.org
Subject: inconsistency between bash and zsh subshells
Date: Mon, 23 May 2022 11:55:09 -0500 [thread overview]
Message-ID: <CAOLfK3XuyVFK16yxjgFCYRbtEYHJ7m5_XmxfsrmAHi7GYdt3Lw@mail.gmail.com> (raw)
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Greetings zsh-users,
I'm using zsh 5.8.1 (Debian).
I am seeing inconsistent behavior between using a subshell in the branch of
a conditional in bash and zsh.
zsh:
zsh$ rm -f /tmp/FOO
zsh$ ls /tmp/FOO 2> /dev/null || echo "no /tmp/FOO"
no /tmp/FOO
zsh$ echo | while read LINE; do IP=$(echo $LINE | cut -d ' ' -f 1); if [ -n
"$IP" ]; then echo FOO; FOO=$(touch /tmp/FOO); else echo BAR; fi; done; ls
/tmp/FOO 2> /dev/null || echo "no /tmp/FOO"
BAR
/tmp/FOO
Why does the subshell in zsh get executed even though the conditional
branch is not? That is, the "touch"-ing of /tmp/FOO.
bash:
bash$ rm -f /tmp/FOO
bash$ ls /tmp/FOO 2> /dev/null || echo "no /tmp/FOO"
no /tmp/FOO
bash$ echo | while read LINE; do IP=$(echo $LINE | cut -d ' ' -f 1); if [
-n "$IP" ]; then echo FOO; FOO=$(touch /tmp/FOO); else echo BAR; fi; done;
ls /tmp/FOO 2> /dev/null || echo "no /tmp/FOO"
BAR
no /tmp/FOO
The bash output is what I would expect zsh to execute/output as well.
Thanks for helping me understand this.
Cheers!
-m
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next reply other threads:[~2022-05-23 16:56 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2022-05-23 16:55 Matt Zagrabelny [this message]
2022-05-23 17:01 ` Mikael Magnusson
2022-05-23 17:26 ` Matt Zagrabelny
2022-05-23 17:31 ` Mikael Magnusson
2022-05-23 17:51 ` Matt Zagrabelny
2022-05-23 17:04 ` Dominik Vogt
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