Re: indirect assignment to array

[Pier Paolo Grassi <pierpaolog@gmail.com>]

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Thanks! I was afraid I had to resort to eval.
By the way, I was trying to create an helper function like this:

debugvar(){
    typeset -g $1
    typeset +m $1
    typeset $1
}

but I found out from the manual that -g "it has no effect when listing
existing parameters"

is there a way to use typeset from functions to print out the definition of
global variables?

thanks again

Pier Paolo Grassi


Il giorno gio 16 apr 2020 alle ore 01:13 Mikael Magnusson <mikachu@gmail.com>
ha scritto:

> On 4/16/20, Pier Paolo Grassi <pierpaolog@gmail.com> wrote:
> > Hello, I'm trying to assign the content of an array to another which name
> > is contained in a variable
> > What I tried:
> >
> > varname=newarray
> > typeset -a array=(1 2 3)
> > typeset -a $varname=($array)
> >
> > but I get an
> > zsh: bad pattern: newarray=(1
> >
> > are there other methods to do indirect assignment that allow me to do
> this?
>
> : ${(PA)varname::=$array}
> (leave out the A for scalar assignment, and use AA for assoc arrays).
>
> --
> Mikael Magnusson
>