on 5-8 I get: > a=(sa\ bb cc\ dd); a=${(qqq)a} > typeset -p a typeset a='"sa bb cc dd"' Pier Paolo Grassi Il giorno mar 28 set 2021 alle ore 18:04 Bart Schaefer < schaefer@brasslantern.com> ha scritto: > On Tue, Sep 28, 2021 at 4:39 AM Pier Paolo Grassi > wrote: > > > > a=(sa\ bb cc\ dd); a=${(qq@)"${a[@]}"}; typeset -p a; echo -e $a > > It should be sufficient to do > > a=${(qqq)a} >