Fwd: Could you provide bash's \$ which like zsh %#?

Fwd: Could you provide bash's \$ which like zsh %#?

[Geoff Wing]

Please CC replies to Daniel.

----- Forwarded message from Daniel Lin <dlin.tw@gmail.com> -----

I'm trying to move from bash to zsh.
I found a problem.  My 'expect' scripts require a '$' sign to let me know
its done.

In zsh the %# will display % when user's effective id is not 0.
But, I require another similar function which display '$' instead of '%'.

Could you consider to add this function to help bash users' life easier?

I already change my PS1="\\$"
But its function is not equal to %#.

----- End forwarded message -----

Re: Could you provide bash's \$ which like zsh %#?

[Jos Backus]

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On Tue, Dec 6, 2011 at 8:43 PM, Geoff Wing <gcw@zsh.org> wrote:

> Please CC replies to Daniel.
>
> ----- Forwarded message from Daniel Lin <dlin.tw@gmail.com> -----
>
> I'm trying to move from bash to zsh.
> I found a problem.  My 'expect' scripts require a '$' sign to let me know
> its done.
>
> In zsh the %# will display % when user's effective id is not 0.
> But, I require another similar function which display '$' instead of '%'.
>
> Could you consider to add this function to help bash users' life easier?
>
> I already change my PS1="\\$"
> But its function is not equal to %#.
>
> ----- End forwarded message -----
>

How about using `%(,,)'?

Example prompt string:

%m:%~%# %(#,$,%%)

-- 
Jos Backus
jos at catnook.com

Re: Could you provide bash's \$ which like zsh %#?

[Daniel Lin]

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Sorry, I've tried, it display strange things.
PS1='%# %(#,$,%%)'

2011/12/7 Jos Backus <jos@catnook.com>

>
>
> On Tue, Dec 6, 2011 at 8:43 PM, Geoff Wing <gcw@zsh.org> wrote:
>
>> Please CC replies to Daniel.
>>
>> ----- Forwarded message from Daniel Lin <dlin.tw@gmail.com> -----
>>
>> I'm trying to move from bash to zsh.
>> I found a problem.  My 'expect' scripts require a '$' sign to let me know
>> its done.
>>
>> In zsh the %# will display % when user's effective id is not 0.
>> But, I require another similar function which display '$' instead of '%'.
>>
>> Could you consider to add this function to help bash users' life easier?
>>
>> I already change my PS1="\\$"
>> But its function is not equal to %#.
>>
>> ----- End forwarded message -----
>>
>
> How about using `%(,,)'?
>
> Example prompt string:
>
> %m:%~%# %(#,$,%%)
>
> --
> Jos Backus
> jos at catnook.com
>

Re: Could you provide bash's \$ which like zsh %#?

[Jos Backus]

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Fwiw, here's what I am seeing (on FreeBSD -current using zsh 4.3.12):

lizzy:~% % PS1='%# %(#,$,%%) '
% %
% %
% % sudo -s
lizzy:/home/jos# PS1='%# %(#,$,%%) '
# $
# $

On Tue, Dec 6, 2011 at 9:03 PM, Daniel Lin <dlin.tw@gmail.com> wrote:

> PS1='%# %(#,$,%%)'



-- 
Jos Backus
jos at catnook.com

Re: Could you provide bash's \$ which like zsh %#?

[Daniel Lin]

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I got the description on 'man zshmisc'

       %#     A  `#'  if  the  shell is running with privileges, a `%' if
not.
              Equivalent to `%(!.#.%%)'.  The definition of `privileged',
 for
              these  purposes,  is  that either the effective user ID is
zero,
              or, if POSIX.1e capabilities are supported, that  at  least
 one
              capability  is  raised  in  either  the Effective or
Inheritable
              capability vectors.

So, to match the document, I should change the prompt to
PS1='%(!.#.$)'

2011/12/7 Jos Backus <jos@catnook.com>

> What do you mean by 'document'?
>
> Jos
> On Dec 6, 2011 9:35 PM, "Daniel Lin" <dlin.tw@gmail.com> wrote:
>
>> I think it may workable by following setting.
>> But, I don't know how to get its document.
>>
>> zsh --version                                                   ~
>> 13:29:54 (1)
>> zsh 4.3.12 (i686-pc-linux-gnu)
>>
>> PS1='%(#,#,$)'  # simulate bash's \$
>> in normal user, it will display $
>> in super user, it will display #
>>
>> 2011/12/7 Jos Backus <jos@catnook.com>
>>
>>> Fwiw, here's what I am seeing (on FreeBSD -current using zsh 4.3.12):
>>>
>>> lizzy:~% % PS1='%# %(#,$,%%) '
>>> % %
>>> % %
>>> % % sudo -s
>>> lizzy:/home/jos# PS1='%# %(#,$,%%) '
>>> # $
>>> # $
>>>
>>> On Tue, Dec 6, 2011 at 9:03 PM, Daniel Lin <dlin.tw@gmail.com> wrote:
>>>
>>>> PS1='%# %(#,$,%%)'
>>>
>>>
>>>
>>> --
>>> Jos Backus
>>> jos at catnook.com
>>>
>>
>>

Re: Could you provide bash's \$ which like zsh %#?

[Bart Schaefer]

On Dec 7,  1:03pm, Daniel Lin wrote:
} Subject: Re: Could you provide bash's \$ which like zsh %#?
} 
} Sorry, I've tried, it display strange things.
} PS1='%# %(#,$,%%)'

That was Josh's attempt to give you one example that shows both %#
and a conditional string that displays something not quite the same,
so that you could compare the two.  It was not intended to be the
prompt that you would use, just a sample of what could be done.

On Dec 7,  3:04pm, Daniel Lin wrote:
} Subject: Re: Could you provide bash's \$ which like zsh %#?
}
} So, to match the document, I should change the prompt to
} PS1='%(!.#.$)'

Yes, almost.  You probably want the trailing space in there.

PS1='%(!.#.$) '

Equivalently, %(#,#,$) says "if the UID is zero, pound, else dollar"
"Running with privileges" could mean something other than "running as
the root user" in obscure circumstances.  %(#,,) is the generalized
form of %(!,,), so that you can test for explicit UID; the default
when no UID is given is zero.  So another possible example is

PS1='%(2#,Running as daemon ,)%(!.#.$) '

[Assuming that UID 2 is "daemon" as it is on my Linux box.]

Re: Could you provide bash's \$ which like zsh %#?

[Daniel Lin]

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Thanks, learn a lot.

2011/12/7 Bart Schaefer <schaefer@brasslantern.com>

> On Dec 7,  1:03pm, Daniel Lin wrote:
> } Subject: Re: Could you provide bash's \$ which like zsh %#?
> }
> } Sorry, I've tried, it display strange things.
> } PS1='%# %(#,$,%%)'
>
> That was Josh's attempt to give you one example that shows both %#
> and a conditional string that displays something not quite the same,
> so that you could compare the two.  It was not intended to be the
> prompt that you would use, just a sample of what could be done.
>
> On Dec 7,  3:04pm, Daniel Lin wrote:
> } Subject: Re: Could you provide bash's \$ which like zsh %#?
> }
> } So, to match the document, I should change the prompt to
> } PS1='%(!.#.$)'
>
> Yes, almost.  You probably want the trailing space in there.
>
> PS1='%(!.#.$) '
>
> Equivalently, %(#,#,$) says "if the UID is zero, pound, else dollar"
> "Running with privileges" could mean something other than "running as
> the root user" in obscure circumstances.  %(#,,) is the generalized
> form of %(!,,), so that you can test for explicit UID; the default
> when no UID is given is zero.  So another possible example is
>
> PS1='%(2#,Running as daemon ,)%(!.#.$) '
>
> [Assuming that UID 2 is "daemon" as it is on my Linux box.]
>