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To: Zsh Users <zsh-users@sunsite.dk>
Subject: Re: Per line ${..//..} 
In-reply-to: <20051026094047.GA658@DervishD> 
References: <20051026094047.GA658@DervishD>
Comments: In-reply-to DervishD <zsh@dervishd.net>
   message dated "Wed, 26 Oct 2005 11:40:47 +0200."
Date: Wed, 26 Oct 2005 10:47:58 +0100
From: Peter Stephenson <pws@csr.com>
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DervishD wrote:
>     I have a parameter containing a bunch of lines, and I have to get
> rid of comments (that is "$line" == (#s)[" $'\t'"]#\#*(#e)) and empty
> lines (that is "$line" == (#s)[" $'\t'"]#(#e)). I've tried using the
> ${..//..} syntax for doing substitutions in parameters, but with no
> success because I don't know how to properly mark the beginning and
> end of a line.

You can do something like:

% lines=(foo "# comment" bar "    ")
% print -l $lines
foo
# comment
bar

% print -l ${lines:#[[:space:]]#(\#*|)}
foo
bar

pws



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