From: Justin M Wozniak <jwozniak@cse.nd.edu>
To: zsh-users@sunsite.dk
Subject: Re: print entire array *with* subscript?
Date: Fri, 10 Feb 2006 23:15:41 -0500 (EST) [thread overview]
Message-ID: <Pine.GSO.4.58.0602102314580.139@cse.nd.edu> (raw)
In-Reply-To: <EXCHANGE03XHbQbilav0000bbe8@exchange03.csr.com>
In your solution, what is the point of (r) ?
--
Justin Michael Joseph Wozniak
On Fri, 10 Feb 2006, Peter Stephenson wrote:
> Jean-Rene David wrote:
> > It would be nice to be able to do this:
> >
> > print ${(k)files}
> > 1 foo.h 2 foo.c 3 bar.h 4 bar.c
> >
> > instead of:
> >
> > for f in {1..$#files}; do
> > print $f ${files[$f]};
> > done
> >
> > Not a big deal. Just asking because that's what I
> > thought the documentation meant.
>
> I think the documentation for the (k) flag is (for once) reasonably
> clear and accurate:
>
> k If name refers to an associative array, substitute the keys
> (element names) rather than the values of the elements. Used
> with subscripts (including ordinary arrays), force indices or
> keys to be substituted even if the subscript form refers to val-
> ues. However, this flag may not be combined with subscript
> ranges.
>
> This means you can use it with normal arrays, but only with individual
> indices. So:
>
> % print ${(k)files[(r)foo.c]}
> 2
>
> but it doesn't work with a subscript nor with a range nor with the *
> and @ subscripts (which are special ranges).
>
> That doesn't mean this is convenient...
>
>
next prev parent reply other threads:[~2006-02-11 4:16 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
[not found] <200602101756.59858.arvidjaar@mail.ru>
2006-02-10 17:50 ` Jean-Rene David
2006-02-10 18:03 ` Peter Stephenson
2006-02-11 4:15 ` Justin M Wozniak [this message]
2006-02-11 5:20 ` Bart Schaefer
2006-02-09 19:40 Jean-Rene David
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