ls most recent files in a hierarchy

ls most recent files in a hierarchy

[zzapper]

I should know this but i'm tired

1) list all the files in a hierarchy modified in last x days

2) list x most recent files in each directory of a hierarchy

3) list x most recent files in a hierarchy

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Re: ls most recent files in a hierarchy

[Christian Schneider]

* zzapper <david@tvis.co.uk> typed:
> I should know this but i'm tired
> 
> 1) list all the files in a hierarchy modified in last x days

ls -tld **/*(m-2) # modified in the last 2 days

> 2) list x most recent files in each directory of a hierarchy

ls **/*(D.om[1,5]) # 5 recent files

> 3) list x most recent files in a hierarchy

ls *(D.om[1,5])
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Re: ls most recent files in a hierarchy

[Lloyd Zusman]

Christian Schneider <strcat@gmx.net> writes:

> * zzapper <david@tvis.co.uk> typed:
>> 
>> [ ... ]
>
>> 2) list x most recent files in each directory of a hierarchy
>
> ls **/*(D.om[1,5]) # 5 recent files

Hmm ... this one seems to list the five most recent files among all the
files in all the directories.  How would we get the 5 most recent files
in _each_ directory of the hierarchy?  In other words, if, for example,
there were 13 directories in the hierarchy, and if each one contained
more than five files, the desired result would contain 65 file names.


-- 
 Lloyd Zusman
 ljz@asfast.com
 God bless you.

Re: ls most recent files in a hierarchy

[Bart Schaefer]

On Mar 16,  2:46am, Christian Schneider wrote:
} Subject: Re: ls most recent files in a hierarchy
}
} > 2) list x most recent files in each directory of a hierarchy
} 
} ls **/*(D.om[1,5]) # 5 recent files

As Lloyd has pointed out, that's actually the answer to #3:

} > 3) list x most recent files in a hierarchy

The answer to #2 is less obvious:

  ls *(ND.om[1,5]) **/*(D/e:'reply=( $REPLY/*(ND.om[1,5]) )':)

That also requires a fairly recent version of zsh; none of the 4.2.x
series has the fix, they'll either crash or go into an infinite loop
when presented with the glob-within-a-glob.

For the 4.2.x line, you need something like:

  dirs=( '' **/*(DM/) ) eval 'ls ${^dirs}*(ND.om[1,5])'

which is perhaps clearer anyway and works in 4.3.x too.

Re: ls most recent files in a hierarchy

[zzapper]

Thanks Zedites

The following is most useful for solving the "What was the name of the file 
I created/modified recently somewhere in this hierarchy" problem

# list 5 most recent files in hierarchy
ls -lt **/*.tex(D.om[1,5]) 


# variation with paging

ls -lt **/*.tex(D.om) | more

Re: ls most recent files in a hierarchy

[Christian Schneider]

Hi,

* Bart Schaefer <schaefer@brasslantern.com> typed:
> On Mar 16,  2:46am, Christian Schneider wrote:
> } Subject: Re: ls most recent files in a hierarchy
> }
> } > 2) list x most recent files in each directory of a hierarchy
> } 
> } ls **/*(D.om[1,5]) # 5 recent files
> 
> As Lloyd has pointed out, that's actually the answer to #3:

Thats correct. I get it wrong. Sorry about that.

> } > 3) list x most recent files in a hierarchy
> 
> The answer to #2 is less obvious:
> 
>   ls *(ND.om[1,5]) **/*(D/e:'reply=( $REPLY/*(ND.om[1,5]) )':)
> 
> That also requires a fairly recent version of zsh; none of the 4.2.x
> series has the fix, they'll either crash or go into an infinite loop
> when presented with the glob-within-a-glob.
> 
> For the 4.2.x line, you need something like:
> 
>   dirs=( '' **/*(DM/) ) eval 'ls ${^dirs}*(ND.om[1,5])'
> 
> which is perhaps clearer anyway and works in 4.3.x too.

Thanks! I can can dispose it on a old^Wstable Debian i also managed.
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