Returning last parameter of a history command

Returning last parameter of a history command

[zzapper]

Hi

how should this done in zsh-speak

history -n -1|sed 's/^.* //

Where the sed returns the last parameter

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Re: Returning last parameter of a history command

[Peter Stephenson]

zzapper wrote:
> Hi
> 
> how should this done in zsh-speak
> 
> history -n -1|sed 's/^.* //
> 
> Where the sed returns the last parameter

zmodload -i zsh/parameter
print ${${(z)history[$((HISTCMD-1))]}[-1]}

Adjust the line number as necessary: it's $((HISTCMD-1)) when you're
getting the previous line at the prompt but it depends where you are
relative to the line being updated.  Experiment.

Note that $history is an associative array; you need to get the line
number in the key exactly right.

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Re: Returning last parameter of a history command

[zzapper]

Peter Stephenson <pws@csr.com> wrote in news:200609221457.k8MEvAhC028569
@news01.csr.com:

> zzapper wrote:
>> Hi
>> 
>> how should this done in zsh-speak
>> 
>> history -n -1|sed 's/^.* //
>> 
>> Where the sed returns the last parameter
> 
> zmodload -i zsh/parameter
> print ${${(z)history[$((HISTCMD-1))]}[-1]}
> 
Thanx PWS

I have adapted this to

print ${${(z)$(history -n -1)}[-1]}

so that I can use on a generic command

I was not able to tell if any of the 3 versions was faster





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Re: Returning last parameter of a history command

[Roman Neuhauser]

# david@tvis.co.uk / 2006-09-22 13:59:00 +0000:
> how should this done in zsh-speak
> 
> history -n -1|sed 's/^.* //

    !$ or alt-dot if I understand your question correctly.

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