From: "Benjamin R. Haskell" <zsh@benizi.com>
To: Frank Terbeck <ft@bewatermyfriend.org>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: Assign to parameter in parameter -- opposite of ${(P)name}?
Date: Sat, 10 Jul 2010 11:36:05 -0400 (EDT) [thread overview]
Message-ID: <alpine.LNX.2.01.1007101133060.4808@hp.internal> (raw)
In-Reply-To: <87fwzst9ys.fsf@ft.bewatermyfriend.org>
On Sat, 10 Jul 2010, Frank Terbeck wrote:
> Benjamin R. Haskell wrote:
> > It's the end of the week, and I'm tired, so I'm sure I'm completely
> > overlooking something obvious, but how do you *assign* to a
> > parameter whose name is in a parameter?
> [...]
> > Do I need to resort to 'eval'?
>
> % typeset foobar=baz
> % print ${foobar}
> baz
>
I was tired... but not thaaat tired... :-)
Using different variable names, I was looking for:
name=xyzzy
value=asdf
# <-- something that doesn't involve the string xyzzy
echo $xyzzy # echoes 'asdf'
next prev parent reply other threads:[~2010-07-10 15:36 UTC|newest]
Thread overview: 8+ messages / expand[flat|nested] mbox.gz Atom feed top
2010-07-09 23:17 Benjamin R. Haskell
2010-07-10 1:13 ` Frank Terbeck
2010-07-10 15:36 ` Benjamin R. Haskell [this message]
2010-07-10 15:44 ` Frank Terbeck
2010-07-10 15:54 ` Benjamin R. Haskell
2010-07-10 14:57 ` Julius Plenz
2010-07-10 15:52 ` Benjamin R. Haskell
2010-07-10 17:39 ` Bart Schaefer
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