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Date: Sat, 10 Jul 2010 11:36:05 -0400 (EDT)
From: "Benjamin R. Haskell" <zsh@benizi.com>
To: Frank Terbeck <ft@bewatermyfriend.org>
cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: Assign to parameter in parameter -- opposite of ${(P)name}?
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On Sat, 10 Jul 2010, Frank Terbeck wrote:

> Benjamin R. Haskell wrote:
> > It's the end of the week, and I'm tired, so I'm sure I'm completely 
> > overlooking something obvious, but how do you *assign* to a 
> > parameter whose name is in a parameter?
> [...]
> > Do I need to resort to 'eval'?
> 
> % typeset foobar=baz
> % print ${foobar}
> baz
> 

I was tired... but not thaaat tired... :-)

Using different variable names, I was looking for:

name=xyzzy
value=asdf

# <-- something that doesn't involve the string xyzzy

echo $xyzzy # echoes 'asdf'