Re: Capturing STDOUT without subshells or file I/O

[Ben Klein <robobenklein@gmail.com>]

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So I just rewrote a large portion of a codebase on being able to use
`printf -v`, but it looks like this support was added after ZSH 5.1,
which I intend to support. (Ubuntu 16.04 still has it.)

So I guess the question is up again, how should I capture the `printf`
output without the `-v` option, no subshells, and no file I/O? Is there
a different method for ZSH v5.1?

I would like to do `printf '%.2f' "3.4" | read var` but it appears that
the command before the pipe causes a subshell to be opened.

Or potentially, is there some way I can make a wrapper that will use
`printf -v` when available, but falls back to another method?


On 09/03/2018 02:43 PM, Joey Pabalinas wrote:
> On Mon, Sep 03, 2018 at 02:02:14PM +0000, Daniel Shahaf wrote:
>> Just pass -v to the builtin printf, e.g.,
>>
>> % printf -v foo 'a%03d' 42
>> % typeset -p foo
>> a042
>> % 
> Much nicer, wow. Looks like I'll be revising quite a few of my scripts
> today.
>

-- 
*\Ben Klein*
Founder and Owner of Robosane, robobenklein@robosane.net
You can find me elsewhere online as 'robobenklein'.
If you need to contact me securely, I am also reachable via GPG, or on
Keybase.

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