* why is (F) about twice as fast as print -l ?
@ 2023-02-06 4:15 sergio
2023-02-06 5:03 ` Bart Schaefer
0 siblings, 1 reply; 2+ messages in thread
From: sergio @ 2023-02-06 4:15 UTC (permalink / raw)
To: zsh-users
l=({1..100000000})
% for i in {1..3}; do time (print ${(F)l} > /dev/null); done
( print ${(F)l} > /dev/null; ) 12.08s user 0.35s system 99% cpu 12.473
total
( print ${(F)l} > /dev/null; ) 11.89s user 0.35s system 99% cpu 12.283
total
( print ${(F)l} > /dev/null; ) 11.99s user 0.37s system 99% cpu 12.414
total
% for i in {1..3}; do time (print -l $l > /dev/null); done
( print -l $l > /dev/null; ) 22.11s user 2.90s system 99% cpu 25.044 total
( print -l $l > /dev/null; ) 22.00s user 3.12s system 99% cpu 25.160 total
( print -l $l > /dev/null; ) 22.15s user 3.01s system 99% cpu 25.216 total
--
sergio.
^ permalink raw reply [flat|nested] 2+ messages in thread* Re: why is (F) about twice as fast as print -l ?
2023-02-06 4:15 why is (F) about twice as fast as print -l ? sergio
@ 2023-02-06 5:03 ` Bart Schaefer
0 siblings, 0 replies; 2+ messages in thread
From: Bart Schaefer @ 2023-02-06 5:03 UTC (permalink / raw)
To: sergio; +Cc: zsh-users
On Sun, Feb 5, 2023 at 8:15 PM sergio <sergio@outerface.net> wrote:
>
> l=({1..100000000})
${(F)l} joins this huge array into a single string and then that
single argument is passed to "print".
print -l $l expands the array and passes all those words to "print",
requiring that they individually be copied at least one extra time.
Incidentally,
print -aC1 $l
is even slower, but
printf "%s\n" $l
is about the same as print -l.
^ permalink raw reply [flat|nested] 2+ messages in thread
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2023-02-06 4:15 why is (F) about twice as fast as print -l ? sergio
2023-02-06 5:03 ` Bart Schaefer
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