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[109.43.114.79]) by smtp.gmail.com with ESMTPSA id o21-20020a170906289500b006d144662b24sm3289084ejd.152.2022.03.18.00.33.27 for (version=TLS1_3 cipher=TLS_CHACHA20_POLY1305_SHA256 bits=256/256); Fri, 18 Mar 2022 00:33:28 -0700 (PDT) From: Leander Jedamus X-Google-Original-From: Leander Jedamus To: Zsh Users Subject: possible bug in zsh concerning a for loop Message-ID: Date: Fri, 18 Mar 2022 08:33:26 +0100 User-Agent: Mozilla/5.0 (X11; Linux armv7l; rv:78.0) Gecko/20100101 Thunderbird/78.14.0 MIME-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Language: de-DE Content-Transfer-Encoding: 8bit X-Seq: 27580 Archived-At: X-Loop: zsh-users@zsh.org Errors-To: zsh-users-owner@zsh.org Precedence: list Precedence: bulk Sender: zsh-users-request@zsh.org X-no-archive: yes List-Id: List-Help: List-Subscribe: List-Unsubscribe: List-Post: List-Owner: List-Archive: Hi! I tried to get a normal for loop to work with zsh. Now I think I found a bug. A short script is ----8<----8<----8<----8<----8<----8<----8<----8<----8<----8<----8<----8< #!/bin/zsh items="item1 item2 item3" for i in $items; do echo "\"$i\"" done ----8<----8<----8<----8<----8<----8<----8<----8<----8<----8<----8<----8< This prints: "item1 item2 item3" It should print: "item1" "item2" "item3" I hope that somebody can verify this. Thanks in advance Leander Jedamus -- .o. _^_ Ich bin nicht das Problem. Ich bin die Lösung.