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Message-id: Date: Wed, 24 Mar 2021 10:19:47 -0700 User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:78.0) Gecko/20100101 Thunderbird/78.8.0 MIME-version: 1.0 Content-type: text/plain; charset=utf-8; format=flowed Content-transfer-encoding: 8bit Content-language: en-US X-Seq: 26590 Archived-At: X-Loop: zsh-users@zsh.org Errors-To: zsh-users-owner@zsh.org Precedence: list Precedence: bulk Sender: zsh-users-request@zsh.org X-no-archive: yes List-Id: List-Help: List-Subscribe: List-Unsubscribe: List-Post: List-Owner: List-Archive: Archived-At: #integer nn=4 typeset -F nn=4 typeset -F aa= (( aa = ((2 * nn) - 1) / (nn**2) )) echo $aa If 'nn' is declared as an integer the above echos zero but if as a float the answer is correct.  But nn will never actually be other than an integer so I don't like to declare it as a float.  Am I not expecting successful arithmetic even with the integer?  I know you can force the issue with: (( aa = ((2 * nn) - 1) / (nn**2.0) )) ... but I wonder why that's needed.  Why are answers dumbed down like that?  It's clearly a design decision but it seems to me unnatural.  If 'aa' was an integer too I understand the result would have to be rounded down to zero, but since aa is a float, shouldn't all arithmetic automatically produce floating point results?