converting parameter to words

converting parameter to words

[Jack McKinney]

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    I have a script that I want to pass multiple arguments to.  These
arguments, however, need to appear with a '-r' in front of them in the
command executed inside the script. For example, if I do this:

$ example this that other

    The script will need to execute

command -r this -r that -r other

    One thought on this was:

#!/bin/zsh

for i
do
  temp="$temp -r $i"
done

command $temp

     Of course, this doesn't work because zsh passing the string inside
$temp as a single argument to the program, instead of parsing it for
words.  From the man page, it sounds like ${^temp} or ${=temp} should
work, but neither does.

- --
"Restore your inalienable human rights.             Jack McKinney
 Vote Libertarian.  http://www.lp.org               http://www.lorentz.com
 http://www.harrybrowne2000.org
F4 A0 65 67 58 77 AF 9B  FC B3 C5 6B 55 36 94 A6    jackmc@lorentz.com

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Re: converting parameter to words

[Nemeth Ervin]

Hi,

"Jack McKinney" <jackmc-zsh-users@lorentz.com> writes:

[...]

> #!/bin/zsh
> 
> for i
> do
>   temp="$temp -r $i"
> done
> 
> command $temp


for i in ...
do
  temp=("$temp[@]" -r "$i")
done

command "$temp[@]"



HTH,
-- 
Ervin
						"Intelligenti pauca."

Re: converting parameter to words

[Bart Schaefer]

On Oct 13, 10:48am, Jack McKinney wrote:
}
} for i
} do
}   temp="$temp -r $i"
} done
} 
} command $temp
} 
} From the man page, it sounds like ${^temp} or ${=temp} should
} work, but neither does.

${=temp} should have done it for you:

zagzig[562] x="foo -r bar -r baz"
zagzig[563] print -l ${=x}
foo
-r
bar
-r
baz

However, it would do the wrong thing if any of the original arguments
contained whitespace.

On Oct 13,  6:16pm, Nemeth Ervin wrote:
}
} for i in ...
} do
}   temp=("$temp[@]" -r "$i")
} done
} 
} command "$temp[@]"

This is the right idea.  Unless you have shwordsplit set (which you must
not, or you wouldn't have needed ${=temp} in the first place) you don't
even need the quotes that Nemeth used; and unless you have shortloops
turned off you can just write it like this:

    local temp i
    for i; temp=($temp -r $i)
    command $temp

-- 
Bart Schaefer                                 Brass Lantern Enterprises
http://www.well.com/user/barts              http://www.brasslantern.com

Zsh: http://www.zsh.org | PHPerl Project: http://phperl.sourceforge.net   

Re: converting parameter to words

[Jack McKinney]

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Big Brother tells me that Bart Schaefer wrote:
> On Oct 13, 10:48am, Jack McKinney wrote:
> }
> } for i
> } do
> }   temp="$temp -r $i"
> } done
> } 
> } command $temp
> } 
> } From the man page, it sounds like ${^temp} or ${=temp} should
> } work, but neither does.
> 
> ${=temp} should have done it for you:
> 
> zagzig[562] x="foo -r bar -r baz"
> zagzig[563] print -l ${=x}

    Yep... this did it.  I found another bone-headed error in the script
that was causing the real problem.

- --
"Restore your inalienable human rights.             Jack McKinney
 Vote Libertarian.  http://www.lp.org               http://www.lorentz.com
 http://www.harrybrowne2000.org
F4 A0 65 67 58 77 AF 9B  FC B3 C5 6B 55 36 94 A6    jackmc@lorentz.com

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Re: converting parameter to words

[Jack McKinney]

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Big Brother tells me that Nemeth Ervin wrote:
> 
> Hi,
> 
> 
> for i in ...
> do
>   temp=("$temp[@]" -r "$i")
> done
> 
> command "$temp[@]"

     Didn't work 8-(.

- --
"Restore your inalienable human rights.             Jack McKinney
 Vote Libertarian.  http://www.lp.org               http://www.lorentz.com
 http://www.harrybrowne2000.org
F4 A0 65 67 58 77 AF 9B  FC B3 C5 6B 55 36 94 A6    jackmc@lorentz.com

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