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To: zsh-users@zsh.org
From: Anssi Saari <as@sci.fi>
Subject: Re: Confused about splitting
Date: Sun, 31 Mar 2019 20:56:03 +0300
Organization: An impatient and LOUD arachnid
Message-ID: <vg3bm1q2ivi.fsf@coffee.modeemi.fi>
References: <vg3k1gf4dmf.fsf@coffee.modeemi.fi>
	<20190331125813.pd45aqx4bvdjnrgr@tarpaulin.shahaf.local2>
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Daniel Shahaf <d.s@daniel.shahaf.name> writes:

> «${=g}» does split the value of the parameter 'g'; you can see that with
> «printf '[%s]' ${=g}».  Then, that intermediate result — an array of words — is
> assigned to the parameter 'first' scalarly, so the value of $first is set to be
> the words of the array joined by spaces as a single string.  That's why «echo
> $first» has the right output.  The «echo $#first» line prints the length of the
> string "$first" in characters, because that's what the «$#foo» syntax does when
> foo is a scalar.

This mistaken idea came from the fact $first[1] is just e with
foofunc3. $first[2] is n, $first[3] is o and so on. For some reason I
thought scalars don't have that but they do.

> The fix is to add back the parentheses to make the assignment an array
> assignment: «first=( ${=g} )».

Thanks.