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From: Bart Schaefer <schaefer@brasslantern.com>
To: zsh-workers@sunsite.dk
Subject: Re: printf for converting numbers to letters, bug?
Date: Sat, 27 Mar 2004 23:53:12 +0000	[thread overview]
Message-ID: <1040327235312.ZM19835@candle.brasslantern.com> (raw)
In-Reply-To: <20040326170042.GA19532@scowler.net>

On Mar 26, 12:00pm, Clint Adams wrote:
} Subject: Re: (Fwd) printf for converting numbers to letters, bug?
}
} > Looks like "%c" is interpreting the argument as a string and printing
} > the first character thereof.  It should work more like %d, shouldn't it?
} 
} Not according to POSIX; the argument to %b, %c, or %s is to be
} interpreted as a string.

Just to clarify my earlier comment:

Zsh is (as of 4.2.0) behaving such that, given x='101',

	printf "%c" $x
and
	print -r $x[1]

produce the same output.  That behavior is nearly useless.  (It is how
/usr/bin/printf on Linux works, though, so I guess it can be interpreted
as a compatibility issue.)
 
} If we had octal brace expansion, he could do something like
} printf "%b\n" \\0{101..145}

If %b interprets the string \0101 as an octal number and prints the
corresponding character, why shouldn't %c interpret the string 101 as a
decimal number and print the corresponding character?

I've just been looking at

  http://www.opengroup.org/onlinepubs/007904975/utilities/printf.html

I notice that although it mentions %b, there's NO definition of %b on any
of the pages it cross-references:

  http://www.opengroup.org/onlinepubs/007904975/basedefs/xbd_chap05.html
  http://www.opengroup.org/onlinepubs/007904975/functions/printf.html

Where is %b defined?


  reply	other threads:[~2004-03-27 23:53 UTC|newest]

Thread overview: 5+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2004-03-26 16:42 (Fwd) " Bart Schaefer
2004-03-26 17:00 ` Clint Adams
2004-03-27 23:53   ` Bart Schaefer [this message]
2004-03-28  4:49     ` Clint Adams
2004-03-29 11:57       ` Oliver Kiddle

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