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From: Bart Schaefer <schaefer@brasslantern.com>
Message-id: <120309142704.ZM16563@torch.brasslantern.com>
Date: Fri, 09 Mar 2012 14:27:04 -0800
In-reply-to: <alpine.LN8.2.00.1203091332580.1456@ckhb06.ckhb.org>
Comments: In reply to "S. Cowles" <scowles@ckhb.org>
 "parameter expansion, substitution" (Mar  9,  2:03pm)
References: <alpine.LN8.2.00.1203091332580.1456@ckhb06.ckhb.org>
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To: zsh-workers@zsh.org
Subject: Re: parameter expansion, substitution
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On Mar 9,  2:03pm, S. Cowles wrote:
} Subject: parameter expansion, substitution
}
} i am not getting expected results in the following code snippet:
}  	b="abc" ; b=${b/#abc%/d} ; echo ${b}
} i expect the value of b to be changed to "d"; however, it remains "abc".

You've misunderstood.  You want:

  	b="abc" ; b=${b/#%abc/d} ; echo ${b}

The # or % or #% must appear at the beginning of the pattern, they are
not positional like ^ and $ in a regular expression.