From: Bart Schaefer <schaefer@brasslantern.com>
To: zsh-workers@zsh.org
Subject: Re: set -e (no && or ||)
Date: Fri, 12 Oct 2012 06:29:23 -0700 [thread overview]
Message-ID: <121012062923.ZM32754@torch.brasslantern.com> (raw)
In-Reply-To: <CAECNH1RQxAH3DvSCVagR_DQHqA6Cpi2U+0p9m3=rhp=kDSnGCQ@mail.gmail.com>
On Oct 12, 12:53pm, Peter Stephenson wrote:
} Subject: Re: set -e (no && or ||)
}
} On Fri, 12 Oct 2012 07:05:41 -0400
} Sergey Fadeev <hindsight@email.com> wrote:
}
} > Why doesn't it exit the shell?
} > $ set -e
} > $ echo $(false)
} > Shouldn't the error code of $(false) command substitution be checked
} > by set -e before passing stdout to the echo builtin?
}
} No, because the command was "echo", and that didn't fail.
The idea being that not every nonzero status is an error, and -e means
to exit on error.
For example, you generally don't want the shell to exit on something
like this:
while read line
then echo This should eventually stop
fi
echo But you probably want to arrive here without exiting
next prev parent reply other threads:[~2012-10-12 13:29 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2012-10-12 11:05 Sergey Fadeev
2012-10-12 11:53 ` Peter Stephenson
2012-10-12 13:29 ` Bart Schaefer [this message]
2012-10-12 13:49 ` Chet Ramey
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