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From: Bart Schaefer <schaefer@brasslantern.com>
Message-Id: <161030105540.ZM14392@torch.brasslantern.com>
Date: Sun, 30 Oct 2016 10:55:40 -0700
In-Reply-To: <20161030152525.GA12137@fujitsu.shahaf.local2>
Comments: In reply to Daniel Shahaf <d.s@daniel.shahaf.name>
        "Re: [BUG] (z)-flag interrupts if $() in input" (Oct 30,  3:25pm)
References: <1477809189.1509250.771544241.795E8177@webmail.messagingengine.com> 
	<20161030152525.GA12137@fujitsu.shahaf.local2>
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To: zsh-workers@zsh.org
Subject: Re: [BUG] (z)-flag interrupts if $() in input
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On Oct 30,  3:25pm, Daniel Shahaf wrote:
}
} "eval $a" returns a parse error in zsh but succeeds in sh.  Let's put
} (z) to one side for the moment;

This actually is a question about (z) rather than about parse errors,
because other parse errors don't have the same problem:

torch% echo ||| print
zsh: parse error near `|'
torch% a='echo ||| print'
torch% print -rl -- ${(z)a}
echo
||
|
print

So the question is not whether $() is a parse error, but why $() eats
the rest of the command line.

Which I think is going to come down to the way cmd_or_math() has to
read ahead to discover whether $( starts a math expresion or a
command substitution -- but I haven't dug in that far.